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A line cuts the x-axis at A (7, 0) and the y-axis at B( 0, - 5 ). A variable line PQ is drawn perpendicular to AB cutting

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A line cuts the x-axis at A (7, 0) and the y-axis at B(0, -5). A variable line PQ is drawn perpendicular to AB cutting the x-axis in P and the y-axis in Q. If AQ and BP intersect at R find the locus of R.

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The equation of the line AB is

Hence, the locus of a point is

x2 + y2 - 7x + 5y = 0.

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