Question

The energy of an electron in the first Bohr orbit of H atom is -13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)

(a)  -3.4 eV

(b)  -4.2 eV

(c)  - 6.8 eV

(d)  +6.8 eV

Answer 1

Correct option (a)  -3.4 eV

Explanation:

The energy of an electron in Bohr's orbit of hydrogen atom is given by the expression.

Hence,  E_n = - E₁(Constant)/n²

Where n takes only integral values. For the first Bohr's orbit, n = 1 and it is given that E_n = - 13.6 eV/n²

of the given values of energy, only -3.4 eV can be obtained by substituting n = 2 in the above expression.