Correct Answer - Option 4 : 1600
Given:
Quantity of A = 18% of total solution
Quantity of B = 40% of total solution
Quantity of C = Total solution – (Total quantity of A and B)
50% of B is withdrawn and the same amount of solution A is put back into the mixture
Initial quantity of C = 160
Calculations:
Let the total solution be 100x
Quantity of A = 100x × 18/100 = 18x
Quantity of B = 100x × 40/100 = 40x
Quantity of C = Total solution – (Total quantity of A and B)
⇒ 100x – (18x + 40x)
⇒ 100x – 58x = 42x
It is given that 50% of B is withdrawn and the same amount of solution A is put back into the
mixture = 50% of B = (50/100) × 40x = 20x
A will be = 18x + 20x = 38x
The quantity of C would be 160 litres more than the final quantity of A
⇒ 42x – 38x = 160
⇒ 4x = 160
⇒ x = 40
Initial quantity of B in the mixture = 40x = 40 × 40 = 1600 litres
∴ Initial quantity of B in the mixture is 1600 litres