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The linear momentum of a body is p = m t + n. Find the force on the particle at time t = 1 second. (m and n are constants).
1. m + n
2. 2m
3. m
4. m - 1

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Correct Answer - Option 3 : m

CONCEPT:

  • Newton’s Second Law of Motion: The rate of change of linear momentum of a body is directly proportional to the external force applied on the body and this change takes place always in the direction of the applied force.
  • According to the second law of motion, force

\(Force \propto \frac{{change\;in\;momentum}}{{time}}\)

\(⇒ F = K\frac{{{p_2} - {p_1}}}{t} = K\frac{{m\left( {v - u} \right)}}{t} = Kma\)          \(\left[ {\therefore \frac{{v - u}}{t} = a} \right]\)

Where, K = constant of proportionality, p = momentum of the body, m = mass of the body, u = initial velocity of the body, v = final velocity of the body, and a = acceleration of the body.

EXPLANATION:

Given that:

momentum (p) = mt + n

According to the second law of motion, force

\(⇒ F =\frac{dp}{dt}\)

\(⇒ F = \frac{d(mt +n)}{dt}\)

⇒ F = m + 0 = m = constant

  • Since the force is always constant which is equal to m. So at time t = 1 second, the force will be equal to m.
  • Therefore option 3 is correct.

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