Correct Answer - Option 1 : 1 and 20
Calculation:
ess = 5% = 0.05
∵ ess is finite with ramp input type of the system is 1
\({K_v} = \frac{1}{{0.05}} = 20\)
Zero – frequency gain of the system = 20
Steady state error for different inputs is given by
Input
|
Type -0
|
Type - 1
|
Type -2
|
Unit step
|
\(\frac{1}{{1 + {K_p}}}\)
|
0
|
0
|
Unit ramp
|
∞
|
\(\frac{1}{{{K_v}}}\)
|
0
|
Unit parabolic
|
∞
|
∞
|
\(\frac{1}{{{K_a}}}\)
|