Correct Answer - Option 4 :
\(\frac{{3\pi}}{{10000}}\)
Concept:
For laminar flow, Maximum velocity occurs at centre.
∴ Umax = Centre–line velocity
For laminar flow, \({U_{avg}} = \frac{{{U_{max}}}}{2} \)
Discharge (Q) = Area × Average velocity
Calculation:
Given:
Pipe diameter, d = 0.04 m, Umax = Centre–line velocity = 1.5 m/s
\({U_{avg}} = \frac{{{U_{max}}}}{2} =\frac{{1.5}}{{2}}\Rightarrow 0.75\) m/s
Discharge (Q) = Area × Average velocity = \( \frac{\pi }{4} \times {\left( {0.04} \right)^2} \times 0.75 =\frac{{3\pi}}{{10000}}\) m3/s.