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A heat engine is producing 20 kW of work, but it can produce 40 kW if it will operate on a reversible cycle. what can be the second law efficiency of the engine?
1. 0.3
2. 0.4
3. 0.5
4. 0.6

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Correct Answer - Option 3 : 0.5

Concept:

The second law efficiency of an engine is given by:

\(\eta_{II}=\frac{W_{actual}}{W_{maximum}}\)

where, Wactual = Actual work produced by the engine, Wmaximum = Maximum work an engine can produce

A reversible engine produced the maximum work.

Explanation:

Given:

Wactual = 20 kW, Wmaximum = 40 kW

\(\eta_{II}=\frac{20}{40}\)

\(\eta_{II}=\frac{1}{2}\)

\(\eta_{II}=0.5\)

Hence the second law efficiency of the heat engine is 0.5

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