Correct Answer - Option 5 : 1
Given:
Maximum marks in the exam = 100
Minimum cutoff marks to clear the exam = 60
Marks scored by Rahane = Marks scored by Virat + 13
Marks scored by Rahane = Marks scored by Pujara – 10
Formula Used:
Average marks scored by all the candidates = Total of marks scored by all the candidates together/Total number of candidates
Calculation:
Let the marks scored by Rahane = x
So, the marks scored by Virat = x – 13, and
The marks scored by Pujara = x + 10
Total of the marks scored by them = 55 × 3 = 165
So, we get:
x + x – 13 + x + 10 = 165
⇒ 3x = 168
⇒ x = 56
Hence, we get:
Marks obtained by Rahane = 56
Marks obtained by Virat = 56 – 13 = 43
Marks obtained by Pujara = 56 + 10 = 66
∵ The minimum cutoff marks is 60, only Pujara, who has scored 66 marks, cleared the exam.
∴ The total number of candidates, among these three who cleared the SBI PO Prelims exam is 1