Correct Answer - Option 4 : 25 kW
Concept:
Power transmitted by a belt:
P = (T1 – T2)V
T1 = Tension on the tight side, T2 = Tension on the slack side, V = velocity of the belt
Calculation:
Given:
D = 200 mm = 0.2 m, \(\frac{{T_1}}{{T_2}}=1.2\), Maximum tension = 240 kN, N = 60 rpm
Since, Between T1 and T2, T1 is always greater than T2.
Therefore, T1 = 240 kN, \(\frac{{T_1}}{{T_2}}=1.2 = T_2=\frac{{240}}{{1.2}}=200~ kN\)
\(V=\frac{{\pi DN}}{{60}}=\frac{{\pi ~×~0.2~×~60}}{{60}}=0.628 ~m/s\)
Power transmitted by the pulley, P = (T1 – T2)V = (240 - 200) × 0.628 = 25.12 kW