LIVE Course for free

Rated by 1 million+ students
Get app now
JEE MAIN 2023
JEE MAIN 2023 TEST SERIES
NEET 2023 TEST SERIES
NEET 2023
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
89 views
in General by (24.2k points)
closed by
The speed at which a four-pole alternator should be driven to generate 50 cycles per second is:
1. 1,400 rpm
2. 500 rpm
3. 1,000 rpm
4. 1,500 rpm

1 Answer

0 votes
by (24.2k points)
selected by
 
Best answer
Correct Answer - Option 4 : 1,500 rpm

Concept:

In an alternator, synchronous speed is

\({N_s} = \frac{{120f}}{P}\)

Where N= Synchronous Speed in rpm

f = supply frequency in Hz

P = number of poles

Rotor speed, Nr = Ns (1 – s)

Calculation:

Number of poles (P) = 4

Frequency (f) = 50

The synchronous speed of the induction motor is,

\({N_s} = \frac{{120 \times 50}}{4} = 1500\;rpm\)

 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...