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The speed at which a four-pole alternator should be driven to generate 50 cycles per second is:
1. 1,400 rpm
2. 500 rpm
3. 1,000 rpm
4. 1,500 rpm

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Correct Answer - Option 4 : 1,500 rpm

Concept:

In an alternator, synchronous speed is

\({N_s} = \frac{{120f}}{P}\)

Where N= Synchronous Speed in rpm

f = supply frequency in Hz

P = number of poles

Rotor speed, Nr = Ns (1 – s)

Calculation:

Number of poles (P) = 4

Frequency (f) = 50

The synchronous speed of the induction motor is,

\({N_s} = \frac{{120 \times 50}}{4} = 1500\;rpm\)

 

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