# A path of uniform width runs round inside the rectangular field of 38 m long and 32 m wide. if the path occupies 600 m2, then the width of the path is

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A path of uniform width runs round inside the rectangular field of 38 m long and 32 m wide. if the path occupies 600 m2, then the width of the path is
1. 30 m
2. 5 m
3. 10 m
4. 15 m

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Correct Answer - Option 2 : 5 m

Given:

A path of uniform width runs round inside the rectangular field of 38 m long and 32 m wide. if the path occupies 600 m2.

Concept used:

Area of rectangle = Length × Breadth

Calculation:

Let the width of path be x m.

Area of rectangular field = 38 × 32 = 1216 m2

Area of rectangular field without path = (38 - 2x) (32 - 2x)

⇒ 1216 - 64x - 76x + 4x2

⇒ 4x2 - 140x + 1216

Area of path

⇒ 1216 - (4x2 - 140x + 1216)

⇒ 140x - 4x2

The path of the rectangular field occupies is 600 m2

⇒ 140x - 4x2 = 600

⇒ 4x2 - 140x + 600

⇒ x2 - 35x + 150

⇒ x2 - 30x - 5x + 150

⇒ x(x - 30) - 5(x - 30)

⇒ (x - 5) (x - 30)

∴ x = 5 because $x \ne 30$

x = 5m is the width of the path.