Correct Answer - Option 2 : 25 days
Given:
M1 = 25
D1 = 10
H1 = 6
M2 = 18
H2 = 10
W2 = 3 × W1
Formula Used:
(M1 × D1 × H1)/W1 = (M2 × D2 × H2)/W2
Where M1 → Initial Men
D1 → Initial day
H1 → Initial hour
M2 → Final men
D2 → Final day
H2 → Final hour
Calculation:
(M1 × D1 × H1)/W1 = (M2 × D2 × H2)/W2
⇒ (25 × 10 × 6)/W1 = (18 × D2 × 10)/(3 × W1)
⇒ (25 × 10 × 6 × 3 × W1)/(18 × 10 × W1)= D2
⇒ D2 = 25
∴ The time taken by 18 men to do 3 times of that work while working 10 hours per day is 25 days.