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25 men can do a work in 10 days while working for 6 hours per day. If they work for 10 hours per day, then in how many days can 18 men do 3 times of that work?
1. 36 days
2. 25 days
3. 31 days 
4. 32 days

1 Answer

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Best answer
Correct Answer - Option 2 : 25 days

Given:

M1 = 25

D1 = 10

H1 = 6

M2 = 18

H2 = 10

W2 = 3 × W1

Formula Used:

(M1 × D1 × H1)/W1 = (M2 × D2 × H2)/W2

Where M1 → Initial Men

D1 → Initial day

H1 → Initial hour

M2 → Final men

D2 → Final day

H2 → Final hour

Calculation:

(M1 × D1 × H1)/W1 = (M2 × D2 × H2)/W2

⇒ (25 × 10 × 6)/W1 = (18 × D2 × 10)/(3 × W1)

⇒ (25 × 10 × 6 × 3 × W1)/(18 × 10 × W1)= D2

⇒ D2 = 25

∴ The time taken by 18 men to do 3 times of that work while working 10 hours per day is 25 days.

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