Correct Answer - Option 2 : 356160
Population of the village 2 years ago (P) = 3,20,000
After increasing (6% = R1), it becomes
By using the formula (1), we have,
⇒ 320000 x (1 + 6/100)
Therefore the population after 1 year = 320000x(1+6/100)1
After increasing (5%=R2), population becomes = 320000x(1+6/100) x (1+5/100)1
Required present population = 320000x(1+6/100) x (1+5/100)
= 320000 x 106/100 x 105/100
= 320 x 53 x 21
= 356160