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The population of a village was 3,20,000 two years ago. If it increased by 6% & 5% respectively in the last two years, then the present population is:
1. 754523
2. 356160
3. 437654
4. 453212
5. 654327

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Correct Answer - Option 2 : 356160

Population of the village 2 years ago (P) = 3,20,000
After increasing (6% = R1), it becomes
By using the formula (1), we have,

⇒ 320000 x (1 + 6/100)
Therefore the population after 1 year = 320000x(1+6/100)1

After increasing (5%=R2), population becomes = 320000x(1+6/100) x (1+5/100)1 

Required present population = 320000x(1+6/100) x (1+5/100)
= 320000 x 106/100 x 105/100
= 320 x 53 x 21
= 356160

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