Correct Answer - Option 1 : 0.156 N/m
Concept:
Surface tension on a liquid droplet (Spherical droplet of water): Pressure intensity inside the droplet:
\(p = \frac{{4\sigma }}{d}\)
Surface tension on a hollow bubble (Soap bubble): Pressure intensity inside the droplet:
\(p = \frac{{8\sigma }}{d}\)
where σ is the surface tension of the liquid.
Calculation:
\({\rm{\Delta }}P = \frac{{8\sigma}}{d}\)
\(\sigma = \frac{{\Delta P\times d}}{8 } =\frac{{25\times 0.05}}{8 }= 0.15625 \ N/m\)
