LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
238 views
in Physics by (24.2k points)
closed by
A negative charge is placed at some point on the line joining the two +Q charges at rest. The' direction of motion of negative charge will depend upon:
1. position of negative charge alone
2. magnitude of negative charge alone
3. Both on the position and magnitude of negative Charge
4. magnitude of negative charge as well as that of positive charges

1 Answer

0 votes
by (24.2k points)
selected by
 
Best answer
Correct Answer - Option 1 : position of negative charge alone

Ans: Option: 1

CONCEPT:

  • Coulomb's law: This law states that the electrostatic force of attraction between two charges is directly proportional to the product of their magnitude and inversely proportional to the square of the distance between them.

\(F= K\frac{Q_1 Q_2}{r^{2}}\)   

Where F = Force of attraction, r = distance between two charges \(Q_1 \) and \(Q_2\) are two charges.

EXPLANATION

According to coulomb's law  \(F= K\frac{Q_1 Q_2}{r^{2}}\)

In question it is mentioned that a negative charge is placed at some point on the line joining the two charges, therefore the force is given as

\(F_1= K\frac{Q_1(-q)}{r_{1}^{2}}\)

\(F_2 = K\frac{Q_2(-q)}{r_{2}^{2}}\)

  • The above equation shows that the direction of motion of the negative charge will depend upon the position of the negative charge alone.

So the correct option is 1.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...