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A negative charge is placed at some point on the line joining the two +Q charges at rest. The' direction of motion of negative charge will depend upon:
1. position of negative charge alone
2. magnitude of negative charge alone
3. Both on the position and magnitude of negative Charge
4. magnitude of negative charge as well as that of positive charges

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Correct Answer - Option 1 : position of negative charge alone

Ans: Option: 1


  • Coulomb's law: This law states that the electrostatic force of attraction between two charges is directly proportional to the product of their magnitude and inversely proportional to the square of the distance between them.

\(F= K\frac{Q_1 Q_2}{r^{2}}\)   

Where F = Force of attraction, r = distance between two charges \(Q_1 \) and \(Q_2\) are two charges.


According to coulomb's law  \(F= K\frac{Q_1 Q_2}{r^{2}}\)

In question it is mentioned that a negative charge is placed at some point on the line joining the two charges, therefore the force is given as

\(F_1= K\frac{Q_1(-q)}{r_{1}^{2}}\)

\(F_2 = K\frac{Q_2(-q)}{r_{2}^{2}}\)

  • The above equation shows that the direction of motion of the negative charge will depend upon the position of the negative charge alone.

So the correct option is 1.

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