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The energy of an excited hydrogen atom is -3.4 eV. The angular momentum of the electron according to Bohr theory is - 
1. 6.8 × 10-33 J s
2. 2.1 × 10-34 J s
 

3. 4.2 × 10-34 J s
4. 1.7 × 10-34 J s

1 Answer

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Best answer
Correct Answer - Option 2 : 2.1 × 10-34 J s
 

The correct answer is option 2) i.e. 2.1 × 10-34 J s

CONCEPT:

According to Bohr's Theory,

  • The energy of an electron (eV) in the nth orbit of H-atom is given by:

E = \(\frac{-13.6}{n^2}\)

  • The angular momentum of an electron in nth orbit is given by:

L = \(\frac{nh}{2\pi}\)

Where h is the Planck's constant (6.627 × 10-34 m2 kg/s)

CALCULATION:

Given that:

Energy of the electron, E = - 3.4 eV

E = \(\frac{-13.6}{n^2}\)

-3.4 = \(\frac{-13.6}{n^2}\) ⇒ n = 2

Angular momentum, L\(\frac{nh}{2\pi} = \frac{2\times 6.627 \times 10^{-34}}{2\pi} = \) 2.1 × 10-34 J s

  •  joules-second (J s) is the SI unit of angular momentum apart from kg m2 s-1.

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