Correct Answer  Option 4 : S 30° E
Concept:
The relation between WCB and RB is given in the table below:
S.no.

Whole circle bearing (WCB)

Reduced bearing (RB)

Quadrant

1

\(0^\circ  90^\circ\)

WCB

NE

2

\(90^\circ  180^\circ\)

180° WCB

SE

3

\(180^\circ  270^\circ\)

WCB  180°

SW

4

\(270^\circ  360^\circ\)

\({\rm{36}}{{\rm{0}}^{\rm{^\circ }}}{\rm{  WCB}}\)

NW

Calculation:
Given,
WCB of a line = 150°
If the value of WCB lies between 90° to 180°, then,
Reduced bearing = 180°  WCB and the line will be in South direction
∴ RB = 180°  150° = 30°
Hence the reduced bearing of a line is S 30° E.