# If the whole circle bearing of a line is 150°, its reduced bearing will be: ______.

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If the whole circle bearing of a line is 150°, its reduced bearing will be: ______.
1. S
2. W
3. S 60° E
4. S 30° E

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Correct Answer - Option 4 : S 30° E

Concept:

The relation between WCB and RB is given in the table below:

 S.no. Whole circle bearing (WCB) Reduced bearing (RB) Quadrant 1 $0^\circ - 90^\circ$ WCB NE 2 $90^\circ - 180^\circ$ 180°- WCB SE 3 $180^\circ - 270^\circ$ WCB - 180° SW 4 $270^\circ - 360^\circ$ ${\rm{36}}{{\rm{0}}^{\rm{^\circ }}}{\rm{ - WCB}}$ NW
Calculation:

Given,

WCB of a line = 150°

If the value of WCB lies between 90° to 180°, then,

Reduced bearing  = 180° - WCB and the line will be in South direction

∴ RB = 180° - 150° = 30°

Hence the reduced bearing of a line is S 30° E.