Correct Answer - Option 4 : S 30° E
Concept:
The relation between WCB and RB is given in the table below:
|
S.no.
|
Whole circle bearing (WCB)
|
Reduced bearing (RB)
|
Quadrant
|
|
1
|
\(0^\circ - 90^\circ\)
|
WCB
|
NE
|
|
2
|
\(90^\circ - 180^\circ\)
|
180°- WCB
|
SE
|
|
3
|
\(180^\circ - 270^\circ\)
|
WCB - 180°
|
SW
|
|
4
|
\(270^\circ - 360^\circ\)
|
\({\rm{36}}{{\rm{0}}^{\rm{^\circ }}}{\rm{ - WCB}}\)
|
NW
|
Calculation:
Given,
WCB of a line = 150°
If the value of WCB lies between 90° to 180°, then,
Reduced bearing = 180° - WCB and the line will be in South direction
∴ RB = 180° - 150° = 30°
Hence the reduced bearing of a line is S 30° E.
