Correct Answer - Option 3 : 1 s
Concept:
time travelled by pressure wave value from tank to tank from the value
\(t=\dfrac{2L}{C}\)
L → Length of Pipe
C → Velocity of pressure wave
Calculation:
Given:
Velocity of pressure wave (C) = 2 m/s
time travelled by pressure wave value from tank to tank from value
\(t=\dfrac{2L}{C}\)
L → Length of Pipe
C → Velocity of pressure wave
if \(t \ge \dfrac{2L}{C}\) → Gradual closure
\(t \le \dfrac{2L}{C}\) → Sudden closure
So, critical time \(t=\dfrac{2L}{C}=\dfrac{2L}{2}\) {for unit length}
t = 1 s
