Correct Answer - Option 2 : 0.4 N/mm
2
Concept
For thin cylindrical vessel:
Hoop stress, \({\sigma _h} = \frac{{pd}}{{2t}}\)
Longitudinal stress, \({\sigma _L} = \frac{{pd}}{{4t}}\)
Volumetric strain, \({\epsilon_v} = \frac{{pd}}{{4tE}}\left( {5 - 4\mu } \right)\)
Calculation:
d = 20 mm, t = 5 mm, p = 0.2 N/mm2,
\({\sigma _h} = \frac{{pd}}{{2t}} = \frac{{0.2 \times 20}}{{2 \times 5}} = 0.4\ N/mm^2\)
For thin spherical vessel:
Hoop stress/Longitudinal stress:
\({\sigma _h} = {\sigma _L} = \frac{{pd}}{{4t}}\)
Hoop strain/longitudinal strain:
\({\epsilon_L} = {\epsilon_h} = \frac{{pd}}{{4tE}}\left( {1 - \mu } \right)\)
Volumetric strain:
\({\epsilon_v} = 3{\epsilon_h} = \frac{{3pd}}{{4tE}}\left( {1 - \mu } \right)\)