Correct Answer - Option 1 : 0.625
Concept:
Form factor: This is defined as the ratio of average width of the basin to the axial length
Form factor \(\rm = \dfrac{B_{avg}}{L_{axial}}\)
Form factor \(\rm=\dfrac{Area}{L× L}\)
Calculation:
Given:
Area of catchment = 62.5 mm2
axial length of catchment = 10 mm
Form factor \(=\dfrac{62.5}{10\times 10}\)
∴ Form factor = 0.625