Correct Answer - Option 3 : 4000 π
Concept:
From uniform wear theory, axial force is given by,
\(W=2π C(r_0-r_i)\)
When the intensity of pressure is maximum at the inner radius : \(C=P_{max}× r_i\)
When the intensity of pressure is minimum at the outer radius: \(C=P_{min}× r_o\)
W = 2π (P ri) (r0 - ri)
Calculation:
Given Pmax = 0.2 MPa, ri = 100 mm = 0.1 m, ro = 200 mm,
W = 2π (0.2 × 106 × 0.1) (200 - 100) × 10-3 = 4000 π