Correct Answer - Option 4 : 66.7%
Concept:
The total transmitted power for an AM system is given by:
\({P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)\)
Pc = Carrier Power
μ = Modulation Index
Calculation:
When the carrier power is suppressed, power saving in the AM wave is carrier power which is not transmitted.
% power saving = (power saved/total power of AM) × 100
\( = \frac{{{P_c}}}{{{P_c}\left( {1 + \frac{{{\mu ^2}}}{2}} \right)}} \times 100\)
\( = \frac{2}{{2 + {\mu ^2}}} \times 100\)
For μ = 1,
\( = \frac{2}{{2 + 1}} \times 100 = 66.67\% \)
