Correct Answer - Option 1 : Men
Given:
5 men can do work in 6 days
6 women can do 40% work in 4 days
3 children can do 75% in 6 days
Calculation:
5 Men = 6 days
⇒ 2 Men = \(\frac{6\; \times \;5}{2}\) = 15 days
⇒ 6 Women = 10 days
⇒ 3 Children = 8 days
⇒ 3 Women = \(\frac{10\; \times \;6}{3}\) = 20 days
⇒ 1 Children = 8 × 3 = 24 days
Total work = LCM of 15, 20 and 24 = 120
2 Men’s one day’s work = 8
3 Women’s one day’s work = 6
1 Child’s one day’s work = 5
Total work of 3 days = 19
Total work of 18 days = 114
Now, it’s 2 Men’s terms
∴ 2 Men will be the last to complete the work.
