Correct Answer - Option 2 : 10 days
Given :
Raju can finish a piece of work in 20 days
Raju worked for 5 days
Jakob finished the remaining work in 15 days
Concept used :
The efficiency of work = 1/(number of days to finish work)
Solution :
Raju worked for 5 days
So, the remaining work will be finished in 15 days by Raju
Jakob can finish the same piece of work in 20 days
The efficiency of Raju = The efficiency of Jakob
One day work of Raju = 1/20
One day work of Jakob = 1/20
One day work working together = (1/20) + (1/20)
⇒ One day work working together = (1 + 1)/20
⇒ One day work working together = 2/20
⇒ One day work working together = 1/10
∴ The number of days they both can finish work together is 10 days.