Question

A square steel rod 20 mm × 20 mm in section is to carry an axial load of 100 kN. Calculate the stress.
1. 2,50,000 kN/m²
2. 1,50,000 kN/m²
3. 3,50,000 kN/m²
4. 4,50,000 kN/m²
5. 6,50,000 kN/m²

Answer 1

Correct Answer - Option 1 : 2,50,000 kN/m²

Concept:

The stress is the ratio of the normal force acting on per unit area,

i.e. \(σ = \frac{P}{A}\)

where P is axial load, A is area 

Calculation:

Given:

Square steel rod 'a' = 20 mm = 20 × 10^-3 m, P = 100 kN 

 Area = 20 × 10-3 × 20 × 10-3 m²

\(Stress (σ )= \frac PA=\frac {100~kN}{20\times 20\times 10^{-6}~m^2}\)

 ∴ σ = 2,50,000 kN/m2