Question

Comprehension

Directions: Read the instructions carefully and answer the question below.

There are six persons – P, Q, R, S, T and W. They have different weights. The weight of the second heaviest person is 120 kg and the weight of the second lightest person is 78 kg. Sum of the weights of S and T is 250 kg. The weight of T is 120. Sum of the weight of W and Q is 128 kg. Only two persons have weight more than P. R is heavier than both W and Q but W is not the lightest.

1. 180
2. 160
3. 178
4. 190
5. 130

Answer 1

Correct Answer - Option 1 : 180

Six persons: P, Q, R, S, T and W.

1) The weight of the second heaviest person is 120 kg.

2) Weight of T is 120. Imply that T is the second heaviest person.

The possible arrangement for the given statements is as follows,

___ > T(120) > ___ > ___ > ___ > ___

3) Only two persons have weight more than P.

4) Sum of the weight of S and T is 250 kg.

S + T = 250

S + 120 = 250

S = 250 - 120 = 130

S(130) > T(120) > P > ___ > ___ > ___

5) the weight of the second lightest person is 78 kg.

6) R is heavier than both W and Q but W is not the lightest. It means W is the second lightest having weight 78 kg.

7) Sum of the weight of W and Q is 128 kg.

W + Q = 128

78 + Q = 128

Q = 128 - 78 = 50

The final arrangement is as follows,

S(130) > T(120) > P > R > W(78) > Q(50)

Sum of the weight of S and Q = 130 +50

180.

Hence, sum of weight of S and Q is 180.