Correct Answer - Option 3 : 4 : 1
Concept:
Rate of cooling is given by the expression ϵσA i.e. Q = ϵσ(πr2)
where ϵ is the emissivity, σ is the Stefan-Boltzmann constant = 5.67 × 10-8 W/m2K4, A = area, T = absolute temperature
The ratio of the diameters of two spherical balls is \(\frac{d_1}{d_2}=\frac{2}{1}\)
Let us assume the diameter of 1st ball is d1 = 2d and diameter of 2nd ball is d2 = d
So, the ratio of the rate of cooling of the big ball as compared to the smaller ball =
\(\frac{{{Q_1}}}{{{Q_2}}} = \frac{{{A_1}}}{{{A_2}}} = \frac{{π d_1^2}}{{π d_2^2}} = {\left( {\frac{{2d}}{d}} \right)^2} = \frac{4}{1}\)
so, the ratio is 4 : 1