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A shaft is driven with the help of a belt, which is passing over the engine and shaft. The engine is running at 200 rpm. The diameters of engine pulley is 51 cm and that of shaft is 30 cm. The speed of the shaft will be:
1. 200 rpm
2. 300 rpm
3. 340 rpm
4. 400 rpm

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Correct Answer - Option 3 : 340 rpm

Explanation:

Let us assume the power transmitted by belt from shaft to the engine is same i.e. neglect the friction loss.

So, power transmitted by shaft = power transmitted to engine

i.e. (Tω)shaft = (Tω)engine

Velocity of belt to the shaft = velocity of shaft to the engine

Vshaft = Vengine 

\((\frac{\pi DN}{60})_{shaft}=(\frac{\pi DN}{60})_{engine}\)

\({DN}_{shaft}={DN}_{engine}\)

Calculation:

Given:

Dshaft = 30 cm, Dengine = 51 cm, Nengine = 200 rpm

51 × 200 = Nshaft × 30 

Nshaft = 340 rpm

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