Question

For transverse electric waves between parallel plates, the lowest value of m, without making all the field components zero, is equal to
1. 3
2. 2
3. 1
4. 0

Answer 1

Correct Answer - Option 3 : 1

Concept:

For parallel plate waveguide, the propagation constant is defined as:

\(\beta = \frac{{m\pi }}{a}\)

a = distance between the plates

Where the minimum value of m = 1

Cut-off frequency for the parallel plate waveguide is given by:

\({f_c} = \frac{m}{{2a}}\)

The wavelength will be:

\({\lambda _c} = \frac{{2a}}{m}\)