Correct Answer - Option 1 : 48
Given:
Pipe A can fill the cistern = 16 hours
Pipe B can fill the cistern = 24 hours
Pipe C can empty the cistern = 12 hours
Formula used:
Total capacity = LCM
Efficiency = Total Capacity/Time
Concept used:
Efficiency of outlet pipe is always in negative
Calculations:
Total work = LCM (16, 24, 12) = 48 units
Efficiency of pipe A = 48/16 = 3 units
Efficiency of pipe B = 48/24 = 2 units
Efficiency of pipe C = 48/12 = -4 units
When all pipes are opened then effective rate at which tank will fill = 3 + 2 – 4 = 1
Require time = 48/1 = 48 hours
∴ Time taken by A, B and C to fill the tank together is 48 hours