Correct Answer  Option 4 : 0.01 mm per sec
Concept:

Drift Velocity: The average speed of electrons by which they slowly move inside a conductor under influence of an applied electric field is called drift velocity.

Drift velocity of the electrons is calculated by:
\(v_d=\frac{I}{neA}\)
I is current in the conductor, e is the electronic charge, n is the number of free electrons per unit volume A is crosssectional Area.
Calculation:
Given,
The number of free electrons per unit volume n = 8.4 × 10 ^{22} / cm ^{3}
Current I = 1.344 A
Crosssectional Area A = 1 mm^{2} = 10 ^{2 }cm ^{2}
Electronic charge e = 1.602 × 10 ^{19} C
Drift velocity from the above expression will be
\(v_d = \frac{1.344}{(8.4 \times 10^{22})(1.6 \times 10^{19})(10^{2})}\)
⇒ v_{d }= 10 ^{2} cm / sec
1 cm = 10 mm
So drift velocity (mm /sec) is
v_{d }= 10 1 mm / sec
So, correct option is 0.1 mm per sec