Correct Answer - Option 2 :

3 × 10^{9} N/m^{2}
__Concept:__

The **bulk modulus of elasticity** of the liquid is given by

\(\rm K = - \dfrac{{{{Δ }}P}}{{\left( {\dfrac{{{{Δ }}V}}{V}} \right)}}\;\)

__Calculation:__

**Given:**

P_{1} = 3 MN/m^{2}, P_{2} = 6 MN/m^{2}, and ΔV = 0.1%

ΔP = P_{2} - P_{1} = 6 – 3 = 3 MN/m^{2}, \(\rm {Δ V\over V}=-0.001\)

\(\rm K = - \dfrac{{3 \times {{10}^6}}}{{ - 0.001}} = 3 \times {10^9}\;N/{m^2}\)