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How many 3 × 8 line decoders with an enable input line are needed to construct a 6 × 64 line decoder without using any other logic gate?
1. 7
2. 8
3. 9
4. 10

1 Answer

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Best answer
Correct Answer - Option 3 : 9

Concept:

Decoder expansion

n1 × m1 → n2 × m2

D1             D2

Number of D2 decoder required = ∑ K

\(\frac{{{m_2}}}{{{m_1}}} = {K_1}\)

\(\frac{{{K_1}}}{{{m_1}}} = {K_2}\)

\(\frac{{{K_2}}}{{{m_1}}} = {K_3}\)

Till 0 or 1

Calculation:

Given decoder 1 is 3 × 8 and the second decoder is 6 × 64

\(\frac{{64}}{8} = 8\)

\(\frac{8}{8} = 1\)

Number of 3 × 8 decoders = 8 + 1

Number of 3 × 8 decoders = 9

Important Points

Given

Decoder

To be implemented

Required

2 x 4

4 x 16

4 + 1 = 5

2 x 4

3 x 8

2 + 0 = 2

3 x 8

6 x 64

8 + 1 = 9

4 x 16

6 x 64

4 + 0 = 4

4 x 16

8 x 256

16 + 1 = 17

 

 

 

 

 

 

 

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