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Consider a CIDR network address 194.24.0.0/21. The last address in this network will be:
1. 194.24.7.255
2. 194.24.11.255
3. 194.23.7.255
4. 194.24.7.250

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Correct Answer - Option 1 : 194.24.7.255

Here, no. of mask bits = network id = n = 21

In classless addressing, no. of address are given by 232-n

For last address set 32 – n rightmost bits to 1.

 

i.e. set 11 rightmost bits to 1.

194.24.0000 0000. 0000 0000

194.24.0000 0111. 1111 1111

The last address in this network will be 194.24.7.255

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