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If ma = mass of dry air and mw = mass of water vapour in the air-water vapour mixture, then humidity ratio is given by-
1. mw / ma
2. ma / mw
3. (mw + ma) / mw
4. ma / (ma + mw)

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Best answer
Correct Answer - Option 1 : mw / ma

Concept:

Humidity ratio/Specific humidity (ω ) (kg/kg) of a given moist air sample is defined as the ratio of the mass of water vapour (mw) to the mass of dry air (ma) contained in the sample.

\(w = \frac{{{m_w}}}{{{m_a}}} = 0.622\frac{{{P_v}}}{{P - {P_v }}} \)

Relative humidity (ϕ):

It is defined as the ratio of  f water vapour (pv)in a mixture to the saturation pressure (ps) of pure water at the same temperature of the mixture.

\(\phi = \frac{{{p_v}}}{{{p_{vs}}}}\)

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