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The smallest integer that can be represented by an 8- bit number in 2’s complement form is
1. -256
2. -128
3. 127
4. -255

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Correct Answer - Option 2 : -128

The Correct Answer is -128.

  • The smallest integer that can be represented by an 8- bit number in 2’s complement form is -128.
  • The sign bit is the most important bit.
  • 00000001 is +1, a number which is positive.
  • So, the range of 8-bit complement numbers of two is -128 to 127, since 128 is not representable (it would be 10000000, but the sign bit rule says that would be a negative number).
  • 10000000 is the most negative figure.
  • The leading 1 tells you it is negative, and you flip all the bits (011111111) to get the magnitude of the number, then add one (10000000 = 128).
  • So -128 is the resulting number.

  • The range of numbers that can be represented by n-bits in 2's complement form is
  • (-2)n-1 to (2n-1) -1
  • Hence, here the smallest number is (-2)7 = -128.

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