Correct Answer - Option 3 :
\(\rm \frac{2a}{y}\)
Concept:
\(\rm \frac{dx^n}{dx}=nx^{n-1}\)
Calculation:
Given: y2 = 4ax
Differentiating with respect to x, we get
\(\rm \Rightarrow {2y}\frac{dy}{dx} = 4a\)
\(\rm \Rightarrow \frac{dy}{dx} = \frac{4a}{{2y}} \)
\(\rm \therefore \frac{dy}{dx} = \frac{2a}{y} \)