Correct Answer - Option 1 : A – 2, B – 3, C – 4, D - 1
Characteristic impedance:
The characteristic impedance of a wave traveling in a lossy medium is given by
\(Z = \sqrt {\frac{{j\omega μ }}{{\sigma + j\omega ϵ}}}\)
Put σ = 0 (free space and lossless medium)
\(Z = \sqrt {\frac{μ_0 }{ϵ_0}}\)
Where,
μ0 = Permeability of free space = 4π x 10-7 H / m
ϵ0 = Permittivity of free space = 8.85 x 10-12 F/m
Poynting vector:
1) It states that the cross product of electric field vector (E) and magnetic field vector (H) at any point is a measure of the rate of flow of electromagnetic energy per unit area at that point that is
\( \vec S = \vec E \times \vec H\)
Where S = Poynting vector, E = Electric field and H = Magnetic field
2) The Poynting vector describes the magnitude and direction of the flow of energy in electromagnetic waves.
3) The unit of the Poynting vector is watt/m2.
Maxwell's Equations for time-varying fields is as shown:
S. No.
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Differential form
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Integral form
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Name
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1.
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\(\nabla \times E = - \frac{{\partial B}}{{\partial t}}\)
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\(\mathop \oint \nolimits_L^{} E.dl = - \frac{\partial }{{\partial t}}\mathop \smallint \nolimits_S^{} B.d S\)
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Faraday’s law of electromagnetic induction
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2.
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\(\nabla \times H =J+ \frac{{\partial D}}{{\partial t}}\)
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\(\mathop \oint \nolimits_L^{} H.dl = \mathop \smallint \nolimits_S^{} (J+\frac{{\partial D}}{{\partial t}}).dS\)
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Ampere’s circuital law
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3.
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∇ . D = ρv
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\(\mathop \oint \nolimits_S^{} D.dS = \mathop \smallint \nolimits_v^{} \rho_v.dV\)
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Gauss’ law
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4.
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∇ . B = 0
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\(\mathop \oint \nolimits_S^{} B.dS = 0\)
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Gauss’ law of Magnetostatics (non-existence of magnetic monopole)
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\(\frac{\partial D}{\partial t}\) = Jd (Displacement Current density)