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Time period of simple pendulum inside the satellite orbiting earth is  
1. Zero
2. 2T
3. T
4. Infinite

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Best answer
Correct Answer - Option 4 : Infinite

The correct answer is Infinite.

CONCEPT:

  • Simple pendulum: A point mass attached to a light inextensible string and suspended from fixed support is called a simple pendulum.
    • The vertical line passing through the fixed support is the mean position of a simple pendulum.

The vertical distance between the point of suspension and the center of mass of the suspended body is called the length of the simple pendulum denoted by L.

The time period of the pendulum:

\(T = 2\pi\sqrt{L/g}\)

where, L = length of string, g = acceleration due to gravity (m/s2)

EXPLANATION:

  • As we know that \(T \alpha \frac{1}{g}\)
  • On an artificial satellite, orbiting the earth, net gravity is zero.

As g = 0, so T = ∞ 

The correct option is ∞ .

The value of g is zero in orbiting satellite:

  • Natural satellites have their own acceleration due to gravity. Artificial satellites don't possess any natural g.
    • Artificial satellites experience a gravitational pull towards earth due to the earth's gravitational force.
    • But as the velocity of artificial satellites is extremely large, so, they have a centrifugal force acting tangentially to the orbit.
    • As the gravitational pull of the earth on the artificial satellite is equal to the centrifugal force acting on the artificial satellite, the net force cancels.

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