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Train crosses a platform of 200 m long in 90 seconds at a speed of 60 km/hr. The time taken by the train to cross an electric pole is ______.
1. 78 sec
2. 30 sec 
3. 52 sec
4. 62 sec

1 Answer

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Correct Answer - Option 1 : 78 sec

Given

Train crosses a platform of 200 m long in 90 seconds

Speed of train = 60 km/hr.

Concept

Speed = (Distance/Time) 

Speed in meter/second = (5/18) km/h

When a train cross a pole it means the length of train is actual distance.

Calculation 

Let the length of train be x meter

Total distance covered by train = length of train + length of platform 

⇒ Total distance covered by train = (x + 200) m.

⇒ Speed of train in meter per second = (5/18) × 60

⇒ Speed of train in meter per second = (50/3) m/s

⇒ (50/3) = (x + 200)/90

⇒ (50 × 90)/3 = x + 200

⇒ 1500 = x + 200 

⇒ x = 1500 - 200 

⇒ x = 1300 meter 

Length of train = 1300 meter 

Now,

⇒ The time taken by the train to cross an electric pole = (1300/(50/3))

⇒ The time taken by the train to cross an electric pole = 78 sec.

∴ The time taken by the train to cross an electric pole is 78 sec.

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