Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
325 views
in Trigonometry by (72.6k points)
closed by
If tan θ + cot θ = 6, then find the value of tan2 θ + cot2 θ.
1. 36
2. 24
3. 26
4. 34

1 Answer

0 votes
by (121k points)
selected by
 
Best answer
Correct Answer - Option 4 : 34

Given:

tan θ + cot θ = 6

Formula Used:

(a + b)2 = a2 + b2 + 2ab

tanθ × cotθ = 1

Calculations:

tan θ + cot θ = 6

Squaring both sides, we get

(tan θ + cot θ)2 = (6)2

⇒ tanθ + cotθ + 2 × tanθ × cotθ = 36

⇒ tanθ + cotθ + 2 × 1 = 36

⇒ tanθ + cotθ = 36 – 2

⇒ tanθ + cotθ = 34

∴ The value of tanθ + cotθ is 34.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...