Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
985 views
in General by (72.6k points)
closed by
The maximum transmission efficiency of an sinusoidal AM signal is ________.
1. 21.68%
2. 33.33%
3. 58.88%
4. 65.55%  

1 Answer

0 votes
by (121k points)
selected by
 
Best answer
Correct Answer - Option 2 : 33.33%

Concept:

The transmission efficiency of an AM wave is defined as the percentage of total power contributed by the sidebands.

For a sinusoidal AM signal, it is given by:

\(η=\frac{{{μ ^2}}}{{2 + {μ ^2}}} \times 100\)

μ = Modulation index

The maximum efficiency is obtained for μ = 1, i.e.

\(η_{max}=\frac{{{1}}}{{2 + {1}}} \times 100\)

ηmax = 33.33 %

Derivation:

Mathematically, the efficiency can be expressed as:

\(\eta = \frac{{{P}_{SB}}}{{{P_t}}} \times 100\%\)

For sinusoidal input

PSB = Sideband power given by:

\({P_{SB}} = \frac{{{P_c}\;{\mu ^2}}}{2}\)

Pt = Total power given by:

\({P_t} = {P_c}\;\left( {1 + \frac{{{\mu ^2}}}{2}} \right)\),

\(\eta = \frac{{{P_c}{\mu ^2}}}{{2\left( {{P_c}\left( {1 + \frac{{{\mu ^2}}}{2}} \right)} \right)}}\)

\(\eta = \frac{{{P_c}{\mu ^2}}}{{{P_c}\left( {2 + {\mu ^2}} \right)}} = \frac{{{\mu ^2}}}{{2 + {\mu ^2}}} \times 100\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...