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In a 4 pole, 25 kW, 200 V wave wound DC shunt generator, the current in each parallel path will be _______.
1. 62.5 A
2. 125 A
3. 31.25 A
4. 250 A

1 Answer

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Correct Answer - Option 1 : 62.5 A

Concept:

The current in each parallel path \(= \frac{I}{A}\)

A is the number of parallel paths

In a wave wound generator, number of parallel paths = 2

In a lap wound generator, number of parallel paths = number of poles

Calculation:

Power (P) = 20 kW

Voltage (V) = 200 V

Total current \(I = \frac{P}{V} = \frac{{25 \times {{10}^3}}}{{200}} = 125\;A\)

Number of parallel paths = 2

The current in each parallel path \(= \frac{{125}}{2} = 62.5\;A\)

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