Correct Answer - Option 2 :
\(5\frac{5}{{47}}\) days
Given:
A and B can do a piece of work in 6 days
B and C can do the same work in 8 days
A and C can do the same work in 10 days.
Calculation:
1 day work of A + B = 1/6
1 day work of B + C = 1/8
1 day work of C + A = 1/10
by adding,
1 day work of 2A + 2B + 2C = 1/6 + 1/8 + 1/10
⇒ 2(A + B + C) = (20 + 15 + 12)/120 = 47/120
⇒ 1 day work of A + B + C = 47/240
∴ The total time of A + B + C is 240/47 is \(5{5\over47}\)days.