Given:-
r1 = 16 cm
r2 = 10 cm
h = 8 cm
Let l be the slant height of the friction clutch, then
l = √(h2 + {r1 - r2}2)
l = √(64 + 36)
l = √100 = 10 cm
L.S.A of friction clutch
= π(r1 + r2)l
= 260π cm2
Volume of friction clutch
= \(\frac{πh}{3}
\)(r12 + r22 + r1r2)
= \(\frac{8π}{3}
\) (256 + 100 + 160)
= \(\frac{8π}{3}
\) × \(\frac{516}{3}
\)
= 8π × 172
= 1376π cm3