Given: a2 = a + d = 38 ….. (1)
a6 = a + 5d = -22 ….. (2)
Subtracting (2) from (1) we get
Now substituting, d = – 15 in equation (1), we get
a + (- 15) = 38 ⇒ a = 38 + 15 = 53
Thus,
a1 = a = 53;
a2 = a + 2d = 53 + 2 × (- 15) = 53 – 30 = 23;
a3 = a + 3d = 53 + 3 × (- 15) = 53 – 45 = 8;
a4 = a + 4d = 53 + 4 × (- 15) = 53 – 60 = – 7