Question

A particle covers 10m in first 5 sec and 10m in next 3 sec. Assuming constant acceleration. Find initial speed, acceleration and distance covered in next 2 sec.

Answer 1

Distance covered in first 5 sec = 10

∴ t₁ = 5 sec, s₁ = 10 m

We know s = ut + 1/2at²  

 

Distance covered in next 3 sec = 10 m

t₂ = 5 + 3 = 8 sec ,s =10 + 10 = 20 m

To find the distance covered in next 2 sec, we have to find the initial speed after 8 sec i.e., the final velocity after 8 sec.

This is the initial speed to find the distance covered in next 2 sec.

∴ Distance covered in next 2 sec = 3 m