|A| = \(\begin{vmatrix}1&2&3\\2&-1&3\\1&2&3\end{vmatrix}\)
= \(1\begin{vmatrix}-1&3\\2&3\end{vmatrix}\) - \(2\begin{vmatrix}2&3\\1&3\end{vmatrix}\)+ \(3\begin{vmatrix}2&-1\\1&2\end{vmatrix}\)
= 1(-3 - 6) - 2(6 - 3) + 3(4 + 1)
= -9 - 6 + 15
= -15 + 15 = 0
\(\because \) Determinant of given matrix is zero.
\(\therefore\) Given matrix is not invertible.