0 votes
212 views
in Physics by (20 points)
edited by

A beam of linearly polarized light is changed into a circularly polarized light by passing it through a slice of crystal 0.003 cm thick. Calculate the difference in the refractive index of the two rays in the crystal assuming this to be the minimum thickness that will produce the effect and that the wavelength is

Please log in or register to answer this question.

1 Answer

0 votes
by (42.2k points)

We know that, when we use quantum wave plate then a linear polarized beam change circular polarized beam.

t1/4 \(\cfrac14\)\(\cfrac{\lambda}{(H_0-H_e)}\)

where, H0 = refractive index of ordinary wave

H= refractive index of extra ordinary wave.

H0 - He\(\cfrac{\lambda}{4t_{t/4}}\)

H0 - He\(\cfrac{6\times10^{-5}}{4\times0.003}\)

H0 - He\(\cfrac{6\times10^{-2}}{12}\)

H0 - He = 0.5 x 10-2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...